(no subject)
Jan. 28th, 2006 12:44 amI beat Dynasty Tactics 2 tonight! W00t!
On the last day of the seminar today, we did a (fictitious) case study about hurricane rebuilding: government agency develops reconstruction plan that involves letting some areas return to nature instead of being rebuilt; some local prefer a plan to put it all back the way it was. Given uncertainties in future storm damage, tax revenues lost, construction cost overruns, lawsuit being brought and possibly lost, and delays during a trial, what's the best plan to go with, which of these things matter, and how much would it be worth to know the outcomes before making your decision? We found the answers and got them right. It was pretty cool!
Also cool: I learned a graphical technique for Bayesian probability calculations that is (for me, at least) about eight million times easier to understand and get right than the standard formulas. Yay for new mental tools!
On the last day of the seminar today, we did a (fictitious) case study about hurricane rebuilding: government agency develops reconstruction plan that involves letting some areas return to nature instead of being rebuilt; some local prefer a plan to put it all back the way it was. Given uncertainties in future storm damage, tax revenues lost, construction cost overruns, lawsuit being brought and possibly lost, and delays during a trial, what's the best plan to go with, which of these things matter, and how much would it be worth to know the outcomes before making your decision? We found the answers and got them right. It was pretty cool!
Also cool: I learned a graphical technique for Bayesian probability calculations that is (for me, at least) about eight million times easier to understand and get right than the standard formulas. Yay for new mental tools!
no subject
Date: 2006-01-28 07:22 am (UTC)no subject
Date: 2006-01-28 02:04 pm (UTC)___B__ __A____/ / \__!B__ ____/ \ ___B__ \_!A____/ \__!B__So the problem is that we know P(A), P(B|A), and P(B|!A) (or some equivalent combination) but we want to know P(A|B), right? Given those values, we can multiply out and assign probabilities to each of the endpoints in this tree: P(AB), P(A!B), P(!AB), and P(!A!B).
The graphical trick is that we can then take the tree and rearrange it:
___A__ __B____/ / \__!A__ ____/ \ ___A__ \_!B____/ \__!A__The endpoint values remain the same, since P(BA) is the same as P(AB). Which means that we can then fill in P(B), since it's just P(BA) + P(B!A), and then the intermediate branch values, P(A|B) and P(!A|B) are easy, because P(B)*P(A|B) = P(AB), so we just divide P(AB) by P(B) to get P(A|B).
It's just the same as memorizing P(A|B) = P(B|A)P(A)/P(B), but it makes more sense to me because the only things you have to remember is that the endpoint value is the product of the branches leading to it, and that pairs of branches sum to 1, both of which are facts that are obvious (to me) in this context.
I think when Prof. Rota taught it, he used a similar analogy involving spatial areas, and it mostly made sense the first time I learned it, but the part that really clicked with this formulation was realizing that the endpoint probabilities are are always the same, and we can reorder the tree leading up to them however we want. It's just rearranging subsets of outcomes to get the grouping we want, and then it's all algebra.
no subject
Date: 2006-01-28 04:27 pm (UTC)no subject
Date: 2006-01-28 09:14 am (UTC)no subject
Date: 2006-01-28 09:31 am (UTC)no subject
Date: 2006-01-28 09:54 am (UTC)And yourself? What fires up your intellectual faculties these days?
no subject
Date: 2006-01-28 10:29 am (UTC)I'm a theoretical bioinformaticist; I apply probabilistic techniques to understand biological sequence data, and (more theoretically) to understand why certain analysis techniques work surprisingly well. It's fun work. I'm also on sabbatical right now, missing a Canadian winter, and instead living in northern California.
no subject
Date: 2006-01-28 02:08 pm (UTC)